It behaves as a voltage differentiator.
Recall the two rules:
Recall the two rules:
- No Current Flows into the Input Terminals
- The Differential Input Voltage is Zero i.e. $V_+ = V_- $
Current through Capacitor = Current through resistor
$ \Rightarrow C \frac{d(V_{in} - 0)}{dt} = \frac{0-V_{out}}{R}$
$ \Rightarrow C \frac{dV_{in}}{dt} = \frac{-V_{out}}{R}$
$ \Rightarrow V_{out} = -RC \frac{dV_{in}}{dt}$
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